Let f(x) = \left \lfloor \frac{2 - 3x}{3x + 3} \right \rfloor. Find f(1) + f(2) + f(3) + ... + f(999) + f(1000).
floor ( 2 - 3x) / (3x + 3)
f(1) = -1
f(2) = -1
....
f(1000) = -1
So
f(1) + f(2) + .....+ f(1000) = 1000 (-1) = -1000
+269 
