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 #1
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To find the sum of f(1) + f(2) + ... + f(40), we can simplify each term and then calculate the sum.

Let's simplify f(n) for any positive integer n:
f(n) = 4n / (sqrt(2n - 1) + sqrt(2n + 1))

To simplify the expression, we can multiply both the numerator and the denominator by the conjugate of the denominator, which is (sqrt(2n - 1) - sqrt(2n + 1)):

f(n) = (4n / (sqrt(2n - 1) + sqrt(2n + 1))) * ((sqrt(2n - 1) - sqrt(2n + 1)) / (sqrt(2n - 1) - sqrt(2n + 1)))

Simplifying further, we get:

f(n) = (4n * (sqrt(2n - 1) - sqrt(2n + 1))) / ((2n - 1) - (2n + 1))
= (4n * (sqrt(2n - 1) - sqrt(2n + 1))) / (-2)

Now we can calculate the sum of f(1) + f(2) + ... + f(40):

sum = f(1) + f(2) + ... + f(40)
= (41(sqrt(21 - 1) - sqrt(21 + 1)))/(-2) + (42(sqrt(22 - 1) - sqrt(22 + 1)))/(-2) + ... + (440(sqrt(240 - 1) - sqrt(240 + 1)))/(-2)
= -2 * (1*(sqrt(21 - 1) - sqrt(21 + 1)) + 2*(sqrt(22 - 1) - sqrt(22 + 1)) + ... + 40*(sqrt(240 - 1) - sqrt(240 + 1)))

Now we can simplify each term in the parentheses and calculate the sum:

sum = -2 * (1*(sqrt(21 - 1) - sqrt(21 + 1)) + 2*(sqrt(22 - 1) - sqrt(22 + 1)) + ... + 40*(sqrt(240 - 1) - sqrt(240 + 1)))
= -2 * (1*(sqrt(1) - sqrt(3)) + 2*(sqrt(3) - sqrt(5)) + ... + 40*(sqrt(79) - sqrt(81)))

We can see that the terms inside the parentheses form a telescoping series, where the square root terms cancel each other out. The only terms that remain are the first and the last:                    YourTexasBenefits Login

sum = -2 * (sqrt(1) - sqrt(3) + sqrt(3) - sqrt(5) + ... + sqrt(79) - sqrt(81))
= -2 * (sqrt(1) - sqrt(81))
= -2 * (1 - 9)
= -2 * (-8)
= 16

Therefore, the sum of f(1) + f(2) + ... + f(40) is 16.

Jul 13, 2023
 #1
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To find the possible values of ab, a+b, a, and b, we'll use the given equations and solve them simultaneously.

(a) Finding all possible values of ab:

From the equation a - b = 4, we can rewrite it as a = b + 4.

Substituting this value of a into the equation a^3 - b^3 = 0, we get:
(b + 4)^3 - b^3 = 0

Expanding the equation, we have:
(b^3 + 12b^2 + 48b + 64) - b^3 = 0

Simplifying the equation, we get:
12b^2 + 48b + 64 = 0

Dividing the equation by 4 to simplify it further, we have:
3b^2 + 12b + 16 = 0

Using the quadratic formula, we can solve for b:
b = (-12 ± √(12^2 - 4316))/(2*3)
b = (-12 ± √(144 - 192))/(6)
b = (-12 ± √(-48))/(6)

Since the discriminant is negative, there are no real solutions for b. Therefore, there are no possible real values for ab.

(b) Finding all possible values of a + b:

Given a - b = 4, we can rewrite it as a = b + 4.

Substituting this value of a into the equation a + b, we get:
(b + 4) + b = 2b + 4

So, the possible values of a + b are all real numbers of the form 2b + 4.

(c) Finding all possible values of a and b:

We have a - b = 4. By substituting the value of a from this equation into the equation a + b = 2b + 4, we get:
(b + 4) + b = 2b + 4

Simplifying the equation, we have:
2b + 4 = 2b + 4

This equation is true for all values of b. Therefore, there are infinitely many possible values for a and b that satisfy the given conditions.

In summary:
(a) There are no possible real values for ab.
(b) The possible values of a + b are all real numbers of the form 2b + 4.
(c) There are infinitely many possible values for a and b that satisfy the given conditions.

Jul 12, 2023