The symbol to the left of the C. Thats a division symbol
12m + 4n = 480------Divide both sides by 4
3m + n = 120---------Subtract n
3m = 120 - n---------Isolate m by dividing both sides by 3
m = (120 - n)/3 -------Simplify if you want
m = 40 - n/3
m = -n/3 =40
The answer is B
Any questions??
(3^8) / (3^5)
3 ^ 8-5
3^3
27
Or plug into web2.0 calc
Could you send another correctly tilted pic??
Then I could do it.
Since each child can be male or female with equal likelihood, there are 2^6 = 64 possible ways in which the genders of the children can be determined. The only way in which Mr. Jones won't have more sons than daughters or more daughters than sons is if he has exactly 3 of each, which can occur in 6C3 = 20 ways. Using the concept of complementary counting gives us that there are 64-20=44 ways in which he can have more children of one gender than the other out of a total of 64 possible ways, for a final probability of 44/64 = 11/16 .
I dont see it. i think he is typing it.
Solve what?
Khan Academy is good
Visit this
https://www.khanacademy.org/math/7th-engage-ny/engage-7th-module-3/7th-module-3-topic-b/v/two-step-equations
-2m-8+4(3m-9)
-2m-8+12m-36----------Combine Like terms
(-2m+12m)+(-8-36)
10m-44
Yes
You mean x = 9?
+355 
