Loading [MathJax]/jax/output/SVG/fonts/TeX/fontdata.js
 
+0  
 
0
1333
4
avatar

Why can't I take (-1)^1/2

 Nov 4, 2015

Best Answer 

 #2
avatar+118696 
+10

Why can't I take (-1)^1/2

 

lets think about this.

This means

 

1

 

Now

 

25=5because55=25sothinkaboutanynegativenumber

 

a positive * a positive = a positive

a negative * a negative = a positive

 

Mmm

you cannot multiply any real number by itself and get a negative answer.  That is impossible !!

So

1

has no real solution!!!

That is why you cannot do it!!

 

 

1

is the basis of the imaginary number system.  It is called i (or sometimes j)

 

i=1

 Nov 4, 2015
 #1
avatar+56 
0

Try (-1)*-0.5

 Nov 4, 2015
 #2
avatar+118696 
+10
Best Answer

Why can't I take (-1)^1/2

 

lets think about this.

This means

 

1

 

Now

 

25=5because55=25sothinkaboutanynegativenumber

 

a positive * a positive = a positive

a negative * a negative = a positive

 

Mmm

you cannot multiply any real number by itself and get a negative answer.  That is impossible !!

So

1

has no real solution!!!

That is why you cannot do it!!

 

 

1

is the basis of the imaginary number system.  It is called i (or sometimes j)

 

i=1

Melody Nov 4, 2015
 #3
avatar
0

Okay super I understand, but what about (1)1/3

 

I think that will be 31

You can say (-1)*(-1)*(-1) = -1, but it still says error?

 Nov 4, 2015
 #4
avatar+118696 
0

Yes you are right.

It is my experience that even very sophisticated calcs can't handle roots of negative numbers. 

I think Alan went into more detail on this once before. Maybe he will comment later. :/

 Nov 4, 2015

2 Online Users

avatar