1/3(8y-2)+1/9(12y+10)=

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Guest Sep 1, 2014

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Best Answer

$$1/3(8y-2)+1/9(12y+10)\\\\
=\frac{(8y-2)}{3}+\frac{12y+10}{9}\\\\
=\frac{(8y-2)*3}{3*3}+\frac{12y+10}{9}$$

Can you take it from here?

Melody Sep 1, 2014

Melody · Answer 1 · 2014-09-01T05:13:33

$$1/3(8y-2)+1/9(12y+10)\\\\
=\frac{(8y-2)}{3}+\frac{12y+10}{9}\\\\
=\frac{(8y-2)*3}{3*3}+\frac{12y+10}{9}$$

Can you take it from here?