1. Determining the angle V between 3pi/2 and pi that satisfying sin v = sin 8pi/9 . The answere can be written as V = a(pi)/b where a/b is a shortened fraction.
2. If tan V = -5/2 which values has then sin2v and cos2v? the answere can be written as sin2v = a/b och cos 2v = c/d. where a/b and c/d shortened fraction.
3. Decide constants A,B and C so that the formula (3cos x - sin x)^2 = Acos3x+Bsin2x+C for all X.