+0

10√​x​​​+3=2√​x​​​+2

0
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10√​x​​​+3=2√​x​​​+2

solve for x

Guest Mar 3, 2015

#2
+91462
+5

10√​x​​​+3=2√​x​​​+2

$$\\10\sqrt{x}+3=2\sqrt{x}+2\\\\ 8\sqrt{x}+3=+2\\\\ 8\sqrt{x}=-1\\\\ \sqrt{x}=\frac{-1}{8}\\\\$$

If the square root is in the question then it is defined to be positive.

So there is no solution to this.

Melody  Mar 4, 2015
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#1
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0

is that $${\mathtt{10}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{x}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{3}} = {\mathtt{2}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{x}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}$$ or $${\mathtt{10}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{3}}}} = {\mathtt{2}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}}}}$$?

TheJonyMyster  Mar 3, 2015
#2
+91462
+5

10√​x​​​+3=2√​x​​​+2

$$\\10\sqrt{x}+3=2\sqrt{x}+2\\\\ 8\sqrt{x}+3=+2\\\\ 8\sqrt{x}=-1\\\\ \sqrt{x}=\frac{-1}{8}\\\\$$

If the square root is in the question then it is defined to be positive.

So there is no solution to this.

Melody  Mar 4, 2015

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