10r+r^2=120 rearrange
r^2 + 10r - 120pi = 0 ........using the onsite solver, we have...
$${{\mathtt{r}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{10}}{\mathtt{\,\times\,}}{\mathtt{r}}{\mathtt{\,-\,}}{\mathtt{120}}{\mathtt{\,\times\,}}{\mathtt{\pi}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{r}} = {\mathtt{\,-\,}}{\sqrt{{\mathtt{5}}}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{24}}{\mathtt{\,\times\,}}{\mathtt{\pi}}{\mathtt{\,\small\textbf+\,}}{\mathtt{5}}}}{\mathtt{\,-\,}}{\mathtt{5}}\\
{\mathtt{r}} = {\sqrt{{\mathtt{5}}}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{24}}{\mathtt{\,\times\,}}{\mathtt{\pi}}{\mathtt{\,\small\textbf+\,}}{\mathtt{5}}}}{\mathtt{\,-\,}}{\mathtt{5}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{r}} = -{\mathtt{25.049\: \!716\: \!168\: \!334\: \!532}}\\
{\mathtt{r}} = {\mathtt{15.049\: \!716\: \!168\: \!334\: \!532}}\\
\end{array} \right\}$$
10r+r^2=120 rearrange
r^2 + 10r - 120pi = 0 ........using the onsite solver, we have...
$${{\mathtt{r}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{10}}{\mathtt{\,\times\,}}{\mathtt{r}}{\mathtt{\,-\,}}{\mathtt{120}}{\mathtt{\,\times\,}}{\mathtt{\pi}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{r}} = {\mathtt{\,-\,}}{\sqrt{{\mathtt{5}}}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{24}}{\mathtt{\,\times\,}}{\mathtt{\pi}}{\mathtt{\,\small\textbf+\,}}{\mathtt{5}}}}{\mathtt{\,-\,}}{\mathtt{5}}\\
{\mathtt{r}} = {\sqrt{{\mathtt{5}}}}{\mathtt{\,\times\,}}{\sqrt{{\mathtt{24}}{\mathtt{\,\times\,}}{\mathtt{\pi}}{\mathtt{\,\small\textbf+\,}}{\mathtt{5}}}}{\mathtt{\,-\,}}{\mathtt{5}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{r}} = -{\mathtt{25.049\: \!716\: \!168\: \!334\: \!532}}\\
{\mathtt{r}} = {\mathtt{15.049\: \!716\: \!168\: \!334\: \!532}}\\
\end{array} \right\}$$