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(27^3)^2*(9^4)^3

 Oct 1, 2014

Best Answer 

 #1
avatar+23247 
+5

To work this without a calculator (such as in an algebra class), write all factors with the same base.

Since the two numbers that aren't exponents are 27 and 9, write both of these in terms of 3.

27  =  3^3        and        9  =  3^2

Replace the  27  and the 9  in the original problem with these values:\ to get:

( (3^3)^3 )^2 x ( (3^2)^4 )^3

Working inside the parenthese first and remembering that you multiply exponents when you raise a power to a power:

( 3^9 )^2 x ( 3^8 )^3

Continue removing powers by multiplying exponents:

3^18 x 3^24

You now need to multiply number with the same base, so add exponents:

3^42

 Oct 1, 2014
 #1
avatar+23247 
+5
Best Answer

To work this without a calculator (such as in an algebra class), write all factors with the same base.

Since the two numbers that aren't exponents are 27 and 9, write both of these in terms of 3.

27  =  3^3        and        9  =  3^2

Replace the  27  and the 9  in the original problem with these values:\ to get:

( (3^3)^3 )^2 x ( (3^2)^4 )^3

Working inside the parenthese first and remembering that you multiply exponents when you raise a power to a power:

( 3^9 )^2 x ( 3^8 )^3

Continue removing powers by multiplying exponents:

3^18 x 3^24

You now need to multiply number with the same base, so add exponents:

3^42

geno3141 Oct 1, 2014

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