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(-2a^4/b)^2

 Sep 1, 2014

Best Answer 

 #1
avatar+118609 
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$$\left(\dfrac{-2a^4}{b}\right)^2\\\\\\
=\dfrac{(-2)^2(a^4)^2}{b^2}\\\\
=\dfrac{4a^8}{b^2}\\\\$$

.
 Sep 1, 2014
 #1
avatar+118609 
+5
Best Answer

$$\left(\dfrac{-2a^4}{b}\right)^2\\\\\\
=\dfrac{(-2)^2(a^4)^2}{b^2}\\\\
=\dfrac{4a^8}{b^2}\\\\$$

Melody Sep 1, 2014

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