(3^-1x^-3y6-2)
$$\\(3^{-1}x^{-3}y^{6}-2)\\\\ =\frac{3^{-1}x^{-3}y^{6}}{1}-2\\\\ =\frac{y^{6}}{3^{+1}x^{+3}}-2\\\\ =\frac{y^{6}}{3x^{3}}-2\\\\ or\\\\ =\frac{y^{6}-6x^{3}}{3x^{3}}\\\\$$
