+0  
 
0
807
1
avatar

(32k^5)^(2/5)= what in terms of k

 May 4, 2017
 #1
avatar+9519 
0

\((32k^5)^{(2/5)}\\ =((2k)^5)^{(2/5)}\\ =(2k)^{(2\cdot5/5)}\\ =(2k)^2\\ =4k^2\)

.
 May 7, 2017

5 Online Users

avatar
avatar
avatar
avatar