(3x^4y^-3z^-1^)^-2

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(3x^4y^-3z^-1^)^-2

Guest Nov 28, 2014

+118613

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Best Answer

$$\\(3x^4y^{-3}z^{-1})^{-2}\\\\
=(3^1x^4y^{-3}z^{-1})^{-2}\\\\
=3^{-2}x^{-8}y^{6}z^{2}\\\\
=\dfrac{y^{6}z^{2}}{3^{2}x^{8}}$$

Melody Nov 29, 2014

Melody · Answer 1 · 2014-11-29T09:12:15

$$\\(3x^4y^{-3}z^{-1})^{-2}\\\\
=(3^1x^4y^{-3}z^{-1})^{-2}\\\\
=3^{-2}x^{-8}y^{6}z^{2}\\\\
=\dfrac{y^{6}z^{2}}{3^{2}x^{8}}$$

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