3x,5x-4,5x are first 3 consecutive terms of an arithmetic sequence . What is its 10th term?
d=5x-(5x-4) = 4
so
5x-4-3x=4
2x=8
x=4
a=3*4=12 d=4
Tn=a+(n-1)d
T10 = 12+9*4 = 48
3x+5x=2*(5x-4)
8x=10x-8
3x=12
d=(5x-3x)/2=4
Thus the 10th term of the sequence is 3x+(10-1)*d=48