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4sin^2x+2cos^2x-3=0 whats x

 May 31, 2015

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 #1
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$$\\4sin^2x+2cos^2x-3=0\\
4sin^2x+2[1-sin^2x]-3=0\\
4sin^2x+2-2sin^2x-3=0\\
2sin^2x-1=0\\
2sin^2x=1\\
sin^2x=\frac{1}{2}\\
sinx=\pm\;\frac{1}{\sqrt2}\\
x=180n\pm\;45\quad degrees\qquad n\in Z \qquad $ (n is an integer)$$$

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 May 31, 2015
 #1
avatar+118608 
+10
Best Answer

$$\\4sin^2x+2cos^2x-3=0\\
4sin^2x+2[1-sin^2x]-3=0\\
4sin^2x+2-2sin^2x-3=0\\
2sin^2x-1=0\\
2sin^2x=1\\
sin^2x=\frac{1}{2}\\
sinx=\pm\;\frac{1}{\sqrt2}\\
x=180n\pm\;45\quad degrees\qquad n\in Z \qquad $ (n is an integer)$$$

Melody May 31, 2015
 #2
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2cos^2 x+4sinx cosx =?

 Jan 24, 2017

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