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(4xy^-3)^4/(2x^2y^-7)

 Apr 1, 2015

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 #1
avatar+118613 
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$$\\\frac{(4xy^{-3})^{4}}{(2x^{2}y^{-7})}\\\\
\frac{(4^4x^4y^{-3*4})}{(2x^{2}y^{-7})}\\\\
\frac{2*4^3x^4y^{+7}}{1x^{2}y^{+12}}\\\\
\frac{128x^{(4-2)}}{y^{(12-7)}}\\\\
\frac{128x^{2}}{y^{5}}\\\\$$

.
 Apr 2, 2015
 #1
avatar+118613 
+5
Best Answer

$$\\\frac{(4xy^{-3})^{4}}{(2x^{2}y^{-7})}\\\\
\frac{(4^4x^4y^{-3*4})}{(2x^{2}y^{-7})}\\\\
\frac{2*4^3x^4y^{+7}}{1x^{2}y^{+12}}\\\\
\frac{128x^{(4-2)}}{y^{(12-7)}}\\\\
\frac{128x^{2}}{y^{5}}\\\\$$

Melody Apr 2, 2015

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