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6x^2 + 8x - 128 = 0 factorize it pls 

 Mar 30, 2015

Best Answer 

 #1
avatar+128731 
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6x^2 + 8x - 128 = 0    divide everything by 2

3x^2 + 4x - 64 = 0       factor...  and set each factor to 0

(3x + 16) (x - 4) = 0

One solution is x = 4

The other is x = -16/3

 

  

 Mar 30, 2015
 #1
avatar+128731 
+5
Best Answer

6x^2 + 8x - 128 = 0    divide everything by 2

3x^2 + 4x - 64 = 0       factor...  and set each factor to 0

(3x + 16) (x - 4) = 0

One solution is x = 4

The other is x = -16/3

 

  

CPhill Mar 30, 2015

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