(-8/x^2-9x)-(9/9x^3-9x^2)

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Guest Mar 4, 2015

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Best Answer

I do not know if this is what you intended but it is what you asked for.

$$\\\frac{-8}{x^2}-9x-(\frac{9}{9}x^3-9x^2)\\\\
=\frac{-8}{x^2}-9x-(x^3-9x^2)\\\\
=\frac{-8}{x^2}-9x-x^3+9x^2\\\\$$

Melody Mar 4, 2015

Melody · Answer 1 · 2015-03-04T01:43:42

I do not know if this is what you intended but it is what you asked for.

$$\\\frac{-8}{x^2}-9x-(\frac{9}{9}x^3-9x^2)\\\\
=\frac{-8}{x^2}-9x-(x^3-9x^2)\\\\
=\frac{-8}{x^2}-9x-x^3+9x^2\\\\$$