\(a-b=5\)
\(ab=2\)
\(a^2+b^2=? \)
\(a^4+b^4=?\)
Hi Daniel, :)
\(a-b=5\\ (a-b)^2=25\\ a^2-2ab+b^2=25\qquad but\;\;ab=2\\ a^2 -2*2+b^2=25\\ a^2 -4+b^2=25\\ a^2 +b^2=29\\~\\ (a^2 +b^2)^2=29^2\\ a^4+2*a^2b^2 +b^4=841\\ a^4+b^4+2ab*ab =841\\ a^4+b^4+2*2*2 =841\\ a^4+b^4+8 =841\\ a^4+b^4=833\\\)
Do you understand it all Daniel?
Yes, thanks
