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A bag contains 3 blue, 8 red, and 11 yellow chips. If 2 chips are drawn with replacement, what is the probability that the first is blue and the second is red?

 Aug 30, 2015

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 #1
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A bag contains 3 blue, 8 red, and 11 yellow chips. If 2 chips are drawn with replacement, what is the probability that the first is blue and the second is red?

 

3/22  * 8/22

 

$$\left({\frac{{\mathtt{3}}}{{\mathtt{22}}}}\right){\mathtt{\,\times\,}}\left({\frac{{\mathtt{8}}}{{\mathtt{22}}}}\right) = {\frac{{\mathtt{6}}}{{\mathtt{121}}}} = {\mathtt{0.049\: \!586\: \!776\: \!859\: \!504\: \!1}}$$

 Aug 30, 2015
 #1
avatar+118608 
+10
Best Answer

A bag contains 3 blue, 8 red, and 11 yellow chips. If 2 chips are drawn with replacement, what is the probability that the first is blue and the second is red?

 

3/22  * 8/22

 

$$\left({\frac{{\mathtt{3}}}{{\mathtt{22}}}}\right){\mathtt{\,\times\,}}\left({\frac{{\mathtt{8}}}{{\mathtt{22}}}}\right) = {\frac{{\mathtt{6}}}{{\mathtt{121}}}} = {\mathtt{0.049\: \!586\: \!776\: \!859\: \!504\: \!1}}$$

Melody Aug 30, 2015

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