A ball is thrown at 40o above the horizontal. The ball is in the air for 4 seconds before it hits. If it travels 38.6 meters before it hits the ground, what was the initial velocity of the ball?
What equaitions should I use to solve this?
Thanks!
+36916 The HORIZONTAL component of the initial velocity does not change (ignoring air friction or other outside forces).
The Horizontal component is given by
vo cos 40 where vo= original velocity
Wed are given that in FOUR seconds it travels 38.6 meters which is a horizotal component of 38.6/4 = 9.65 m/s
Now set these to quantities = to each other and solve for vo
vo cos 40 = 9.65
vo = 9.65 / (cos 40) = 12.597 m/s
