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w(x)=ab^x where : 

a=

b=

 

w(x): (8,40), (40,8)

 Nov 25, 2014

Best Answer 

 #1
avatar+128707 
+5

So we have

40 = ab8  and 8 = ab40

Using the first, we can solve for a  =   40/b8 ........and substituting this into the second, we have

8 =(40/b8)b40  

8 = 40b32        divide both sides by 8

(1/5) = .20 = b32            take the (positive) 32nd root of both sides

b = about .951

And substituting this into 40 = ab8  to find a, we have

40 = a(.951)8        divide both sides by (.951)8 

a = 40 / (.951)8  = about 59.79

So....our function is

w(x) = 59.79(.951)x

 

 Nov 25, 2014
 #1
avatar+128707 
+5
Best Answer

So we have

40 = ab8  and 8 = ab40

Using the first, we can solve for a  =   40/b8 ........and substituting this into the second, we have

8 =(40/b8)b40  

8 = 40b32        divide both sides by 8

(1/5) = .20 = b32            take the (positive) 32nd root of both sides

b = about .951

And substituting this into 40 = ab8  to find a, we have

40 = a(.951)8        divide both sides by (.951)8 

a = 40 / (.951)8  = about 59.79

So....our function is

w(x) = 59.79(.951)x

 

CPhill Nov 25, 2014

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