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A passenger in an airplane at an altitude of 10 kilometers sees two towns directly to the east. The angles of depression to the towns are 27 and 28 degrees. How far apart are the towns?

 Jan 19, 2015

Best Answer 

 #1
avatar+128581 
+10

The answer is given by

10/tan(27) - 10/tan(28) = about .82 km

Here's an approximate diagram.....

 

 

 Jan 19, 2015
 #1
avatar+128581 
+10
Best Answer

The answer is given by

10/tan(27) - 10/tan(28) = about .82 km

Here's an approximate diagram.....

 

 

CPhill Jan 19, 2015
 #2
avatar
+5

Thanks and just for laughs.. what does a butcher weigh? meat.

 Jan 19, 2015
 #3
avatar+118608 
+5

Thanks for the smile anon.  

Great pic Chris    

 Jan 20, 2015
 #4
avatar+128581 
+5

Thanks, Melody.......

 

 Jan 20, 2015

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