a projectile is launched with 60º(from the floor), whith a initial speed called v0.What's the trajectory equation?
The horizontal distance as a function of time is given by x = v0*cos(60°)*t
The vertical distance as a function of time is given by y = v0*sin(60°)*t - g*t2/2 where g is gravitational acceleration.
The above assumes air resistance is negligible.
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