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A recent survey by the American Cancer Society has shown that the probability that someone is a smoker is P(S) = 0.39. It has also determined that the probability that someone has lung cancer, given that he or she is a smoker is P(LC|S) = 0.205. What is the probability (rounded to the nearest hundredth) that a random person is a smoker and has lung cancer P(S ∩ LC)?

 0.03

 0.08

 0.53

 0.07

failurewithasmile  Apr 15, 2017
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 #1
avatar+77125 
+1

We have that

 

P(LC l S )  =  P( LC and S) / P(S)

 

.205   =  P(LC and S) / .39        multiply both sides by 39

 

(.39) (.205)  = P(LC and S)   =  .07995 ≈ .08  

 

 

 

cool cool cool

CPhill  Apr 15, 2017

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