A survey asked students to choose their favorite social networking website. The results are shown in the table.
a. What fraction of the students chose Website A?
b. What percent of the students chose Website C?
There are 80 students in total
fraction choosing A = 35/80 = 7/16
% choosing C = 22/80 = 11/40 = 27.5%
[edited answer ]
CPhill: Just a minor error in the 2nd part:
22/80=11/40=27.50%
Oops....thanks, guest, for catching my mistake.....I've corrected my answer.....!!!
