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−x(2ln(x)+1), x=1/(e)^(1/2)

haziqhasnul Nov 14, 2015

+118609

+10

Best Answer

x(2ln(x)+1), x=1/(e)^(1/2)

\(x(2ln(x)+1),\qquad x=1/(e)^{1/2}=e^{-0.5}\\ =e^{-0.5}(2lne^{-0.5}+1)\\ =e^{-0.5}((2*-0.5)lne+1)\\ =e^{-0.5}((-1)*1+1)\\ =e^{-0.5}(0)\\ =0 \)

Melody Nov 14, 2015

Melody · Answer 1 · 2015-11-14T06:34:30

x(2ln(x)+1), x=1/(e)^(1/2)

\(x(2ln(x)+1),\qquad x=1/(e)^{1/2}=e^{-0.5}\\ =e^{-0.5}(2lne^{-0.5}+1)\\ =e^{-0.5}((2*-0.5)lne+1)\\ =e^{-0.5}((-1)*1+1)\\ =e^{-0.5}(0)\\ =0 \)