Agents J and K work in a long hallway with 4000 equally-spaced, consecutive offices. The agents decide to walk toward each other so they can meet and have lunch together. Agent J has recently been relocated from office 2013 to office 1. His former office neighbor, agent K, is still in office 2014. Assuming that Agent J can walk at a rate of 25 offices per minute, and Agent K walks at 36 offices per minute, what office will they meet at if they leave at the same time?
There are (2014 - 1) - 1 = 2012 offices between them
Each minute they close the distance by (25 + 36) = 61 offices. So....the number of minutes required to close the whole distance is just 2012/61 = about 33 minutes
So 1 + 25(33) = 826 ....and office 826 is approximately where they meet
Proof [ from the other end]..... 2014 - 36(33) = 826
There are (2014 - 1) - 1 = 2012 offices between them
Each minute they close the distance by (25 + 36) = 61 offices. So....the number of minutes required to close the whole distance is just 2012/61 = about 33 minutes
So 1 + 25(33) = 826 ....and office 826 is approximately where they meet
Proof [ from the other end]..... 2014 - 36(33) = 826