+0  
 
0
613
1
avatar

The square root of 68ac^3 divided by the square root of 27a^2

 Apr 1, 2015

Best Answer 

 #1
avatar+128481 
+5

68ac^3 divided by the square root of 27a^2

√ [ 68ac^3] /  √[27a^2]  .... we have

√[68/27] * √[a/a^2] *√c^3  =

(4/3) √(17/3) * √[a/a^2] *√c^3 =

(4/3) √(17/[3a]) * c√c =

(4c/3)√(17c/[3a]) 

 

  

 Apr 1, 2015
 #1
avatar+128481 
+5
Best Answer

68ac^3 divided by the square root of 27a^2

√ [ 68ac^3] /  √[27a^2]  .... we have

√[68/27] * √[a/a^2] *√c^3  =

(4/3) √(17/3) * √[a/a^2] *√c^3 =

(4/3) √(17/[3a]) * c√c =

(4c/3)√(17c/[3a]) 

 

  

CPhill Apr 1, 2015

5 Online Users

avatar