+0

algebra 1

0
112
2

how would you simplify the square root of 128?

Guest Mar 30, 2017
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#1
+4716
+3

$$\sqrt{128}\\=\sqrt{2*2*2*2*2*2*2}\\=\sqrt{2*2}*\sqrt{2*2}*\sqrt{2*2}*\sqrt{2}\\=2*2*2*\sqrt2\\=8\sqrt{2}$$

hectictar  Mar 30, 2017
#2
+90563
+2

OR

$$\sqrt{128}=\sqrt{64}*\sqrt{2}=8\sqrt2$$

Melody  Mar 30, 2017

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