solve algebraically the simultaneous equation

x^2*y^2=25

y-2^x=5

please explain the working outs to me as well

Guest Jun 15, 2017

#1**0 **

solve algebraically the simultaneous equation

x^2*y^2=25

y-2^x=5

please explain the working outs to me as well

I know you asked to " solve algebraically", but I couldn't!!. So, I tried to solve them "heuristically", and I got these results:

x = -0.903404 and y = 5.53462

x = 0.748498 and y = 6.68004

Guest Jun 15, 2017