I feel so bad when solving these types of question.(sin cos tan sec csc cot)
I feel so bad when solving these types of question.(sin cos tan sec csc cot)
Hi XavierZz
Lets see
Reciprocal ratios
cot=1/tan see how the 3rd letter in the less familiar one = the first letter in the 'normal' one
sec=1/cos see the 3rd/1st leter thing again
cosec=1/sin and again (in Australia we write cosec not just csc
Complementary ratios
Remember: Complementary angels add up to 90 degrees
cosineθ=sine(90−θ)andviseversacotangentθ=tangent(90−θ)andviseversacosecθ=sec(90−θ)andviseversa
The 'co' stands for complimentary.
Identities that you need to remember are
cos2θ+sin2θ=1 sin(x+y)=sinxcosy+cosxsiny cos(x+y)=cosxcosy−sinxsiny
Just about everything else can be worked out from there.
I don't think I remember anything much else but most people remember a few more because it takes them too long or it is too difficult for them to derive other things.
NOW IT IS JUST A MATTER OF PRACTICE, PRACTICE AND MORE PRACTICE.
I feel so bad when solving these types of question.(sin cos tan sec csc cot)
Hi XavierZz
Lets see
Reciprocal ratios
cot=1/tan see how the 3rd letter in the less familiar one = the first letter in the 'normal' one
sec=1/cos see the 3rd/1st leter thing again
cosec=1/sin and again (in Australia we write cosec not just csc
Complementary ratios
Remember: Complementary angels add up to 90 degrees
cosineθ=sine(90−θ)andviseversacotangentθ=tangent(90−θ)andviseversacosecθ=sec(90−θ)andviseversa
The 'co' stands for complimentary.
Identities that you need to remember are
cos2θ+sin2θ=1 sin(x+y)=sinxcosy+cosxsiny cos(x+y)=cosxcosy−sinxsiny
Just about everything else can be worked out from there.
I don't think I remember anything much else but most people remember a few more because it takes them too long or it is too difficult for them to derive other things.
NOW IT IS JUST A MATTER OF PRACTICE, PRACTICE AND MORE PRACTICE.