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Find the unknown sides or angles of each of the following tringle. in each y = 90 degrees.

a=62 degrees 40', b=796

B=51 degrees 10', c=0.832

a=37 degrees 40', a=54.8

B=41 degrees 25', c=3265

B= 62 degrees, a=0.8263

B=47 degrees 23', b=72.55

a=24 degrees 47', b=318.4

 

Is this given has two solutions?

 May 10, 2016

Best Answer 

 #2
avatar+128598 
+5

B=51 degrees 10', c=0.832

A = 90 - [51 + 1/6]  = [38 + 1/3] degrees

 

By the Law of Sines

 

 c / sin 90 =  b / sin [ 51 + 1/6]

 

0.832 * sin [ 51 + 1/6]  = b  = about  0.648

 

a = sqrt [ .832^2 - .648^2]  = about  0.5218

 

 

--------------------------------------------------------------------------------------------------------

B=47 degrees 23', b=72.55

 

A  = 90 - [47 + 23/60]  = [42 + 37/60] degrees

 

By the Law of Sines

 

72.55 / sin [47 + 23/60]  =  a / sin [ 42 + 37/60]

 

a =  sin [ 42 + 37/60] * 72.55 / sin [47 + 23/60]  = about 66.75

 

c = sqrt [ 72.55^2 + 66.75^2]  = about 98.59

 

 

 

cool cool cool

 May 10, 2016
 #1
avatar+128598 
+5

Here.....I'm assuming that "c"  is the hypotenuse

 

A =62 degrees 40', b=796

angle B = 90 - (62 +2/3)  = [27 + 1/3]°

 

Using the Law  of Sines

 

796/sinB   = a / sinA

 

796/sin [ 27 + 1/3[  =  a/ sin [62 + 2/3]

 

a = 796[sin 62 + 2/3] / [sin 27 + 1/3]   =  about  1540

 

c = sqrt [ 796^2 + 1540^2  ]  = about 1733.56

 

 

cool cool cool

 May 10, 2016
 #2
avatar+128598 
+5
Best Answer

B=51 degrees 10', c=0.832

A = 90 - [51 + 1/6]  = [38 + 1/3] degrees

 

By the Law of Sines

 

 c / sin 90 =  b / sin [ 51 + 1/6]

 

0.832 * sin [ 51 + 1/6]  = b  = about  0.648

 

a = sqrt [ .832^2 - .648^2]  = about  0.5218

 

 

--------------------------------------------------------------------------------------------------------

B=47 degrees 23', b=72.55

 

A  = 90 - [47 + 23/60]  = [42 + 37/60] degrees

 

By the Law of Sines

 

72.55 / sin [47 + 23/60]  =  a / sin [ 42 + 37/60]

 

a =  sin [ 42 + 37/60] * 72.55 / sin [47 + 23/60]  = about 66.75

 

c = sqrt [ 72.55^2 + 66.75^2]  = about 98.59

 

 

 

cool cool cool

CPhill May 10, 2016
 #3
avatar+185 
0

Thank you so much CPhill. youre our savior. :)

kathh22  May 10, 2016
 #4
avatar+128598 
+5

B=41 degrees 25', c=3265

A =  90  - [ 41 + 25/60] = [48 + 35/60] degrees

Using the Law of sines, we have

 

3265 / sin 90  = a/ sin[ 48 + 35/60]

a = 3265*sin [ 48 + 35/60]   = about  2448.48

 

b = sqrt [ 3265^2  - 2448.48^2 ]  = about   2159.9

 

---------------------------------------------------------------------------

B= 62 degrees 57', a=0.8263

A = 90  - [62 + 57/60]  = [27 + 3/60] degrees

 

a/ sinA   = b / sinB

 

.8263 / sin [ 27 + 3/60]  = b /  sin [ 62 + 57/60]

b =  .8263* sin[62 + 57/60] / sin [27 + 3/60]  = about 1.618

 

C = sqrt [ .8263^2  + 1.618^2 ]  =  about   1.817

 

--------------------------------------------------------------------------

 

A=24 degrees 47', b=318.4

 

B =  90 - [ 24 + 47/60]  =  [ 65 + 13/60] degrees

 

b/ sinB   = a / sin A

 

318.4 / sin[ 65 + 13/60]  = a / sin [ 24 + 47/60]

a = 318.4*sin[24 + 47/60] / sin[65 + 13/60]  = about  147

 

c = sqrt [ 147^2 + 318.4^2]  = about 350.7

 

 

cool cool cool

 May 10, 2016

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