Find the unknown sides or angles of each of the following tringle. in each y = 90 degrees.
a=62 degrees 40', b=796
B=51 degrees 10', c=0.832
a=37 degrees 40', a=54.8
B=41 degrees 25', c=3265
B= 62 degrees, a=0.8263
B=47 degrees 23', b=72.55
a=24 degrees 47', b=318.4
Is this given has two solutions?
B=51 degrees 10', c=0.832
A = 90 - [51 + 1/6] = [38 + 1/3] degrees
By the Law of Sines
c / sin 90 = b / sin [ 51 + 1/6]
0.832 * sin [ 51 + 1/6] = b = about 0.648
a = sqrt [ .832^2 - .648^2] = about 0.5218
--------------------------------------------------------------------------------------------------------
B=47 degrees 23', b=72.55
A = 90 - [47 + 23/60] = [42 + 37/60] degrees
By the Law of Sines
72.55 / sin [47 + 23/60] = a / sin [ 42 + 37/60]
a = sin [ 42 + 37/60] * 72.55 / sin [47 + 23/60] = about 66.75
c = sqrt [ 72.55^2 + 66.75^2] = about 98.59
Here.....I'm assuming that "c" is the hypotenuse
A =62 degrees 40', b=796
angle B = 90 - (62 +2/3) = [27 + 1/3]°
Using the Law of Sines
796/sinB = a / sinA
796/sin [ 27 + 1/3[ = a/ sin [62 + 2/3]
a = 796[sin 62 + 2/3] / [sin 27 + 1/3] = about 1540
c = sqrt [ 796^2 + 1540^2 ] = about 1733.56
B=51 degrees 10', c=0.832
A = 90 - [51 + 1/6] = [38 + 1/3] degrees
By the Law of Sines
c / sin 90 = b / sin [ 51 + 1/6]
0.832 * sin [ 51 + 1/6] = b = about 0.648
a = sqrt [ .832^2 - .648^2] = about 0.5218
--------------------------------------------------------------------------------------------------------
B=47 degrees 23', b=72.55
A = 90 - [47 + 23/60] = [42 + 37/60] degrees
By the Law of Sines
72.55 / sin [47 + 23/60] = a / sin [ 42 + 37/60]
a = sin [ 42 + 37/60] * 72.55 / sin [47 + 23/60] = about 66.75
c = sqrt [ 72.55^2 + 66.75^2] = about 98.59
B=41 degrees 25', c=3265
A = 90 - [ 41 + 25/60] = [48 + 35/60] degrees
Using the Law of sines, we have
3265 / sin 90 = a/ sin[ 48 + 35/60]
a = 3265*sin [ 48 + 35/60] = about 2448.48
b = sqrt [ 3265^2 - 2448.48^2 ] = about 2159.9
---------------------------------------------------------------------------
B= 62 degrees 57', a=0.8263
A = 90 - [62 + 57/60] = [27 + 3/60] degrees
a/ sinA = b / sinB
.8263 / sin [ 27 + 3/60] = b / sin [ 62 + 57/60]
b = .8263* sin[62 + 57/60] / sin [27 + 3/60] = about 1.618
C = sqrt [ .8263^2 + 1.618^2 ] = about 1.817
--------------------------------------------------------------------------
A=24 degrees 47', b=318.4
B = 90 - [ 24 + 47/60] = [ 65 + 13/60] degrees
b/ sinB = a / sin A
318.4 / sin[ 65 + 13/60] = a / sin [ 24 + 47/60]
a = 318.4*sin[24 + 47/60] / sin[65 + 13/60] = about 147
c = sqrt [ 147^2 + 318.4^2] = about 350.7