(z1)^2 = (1 - i√3)^2 = (1 - 2i√3 - 3) = (- 2 - 2i√3) = -2(1 + 2i√3)
(z2)^2 = (√3 + i)^2 = (3 +2i√3 - 1) = ( 2 + 2i√3) = 2( 1 + 2i√3)
So ......
[(z1)^2] / [(z2)^2] = [ -2(1 + 2i√3)] / [2(1 + 2i√3)] = -2/2 = -1 = -1 + 0i = z3
So
tan Θ = (b/a) → tan-1 (b/a) = Θ = arg z3
And
tan-1 (0/-1) = pi
So
arg z3 = pi
(z1)^2 = (1 - i√3)^2 = (1 - 2i√3 - 3) = (- 2 - 2i√3) = -2(1 + 2i√3)
(z2)^2 = (√3 + i)^2 = (3 +2i√3 - 1) = ( 2 + 2i√3) = 2( 1 + 2i√3)
So ......
[(z1)^2] / [(z2)^2] = [ -2(1 + 2i√3)] / [2(1 + 2i√3)] = -2/2 = -1 = -1 + 0i = z3
So
tan Θ = (b/a) → tan-1 (b/a) = Θ = arg z3
And
tan-1 (0/-1) = pi
So
arg z3 = pi