at the beggining of a basketball season, the warrior won 11 games an lost 7 at this rate how many games will they win in a normal 82 game sesason
Well the win 11/18 games
$${\frac{{\mathtt{11}}}{{\mathtt{18}}}}{\mathtt{\,\times\,}}{\mathtt{82}} = {\frac{{\mathtt{451}}}{{\mathtt{9}}}} = {\mathtt{50.111\: \!111\: \!111\: \!111\: \!111\: \!1}}$$
