binets formula 2nd formula

Wow, thanks CPhill! I'll go ahead and do some reading on it!

F(20) = [ Phi^20 - (-phi)^20 ]  / √5   =  [ Phi^20 - (phi)^20 ] / √5  =

( [ (1 + √5) / 2]^20  - [2 / (1 + √5)]^20 )  / √5 =

6765

[ It's quite surprising that dividing by an irrational produces an integer result....!!! ]

Cphil actually helps out and answers relevant questions. I applaud your commitment.

Rarinstraw....here's a whole page devoted to the Fibonacci Series....it's pretty interesting...:

http://www.maths.surrey.ac.uk/hosted-sites/R.Knott/Fibonacci/fibmaths.html#relprime

And here's one dealing with Binet's Formula :

http://www.maths.surrey.ac.uk/hosted-sites/R.Knott/Fibonacci/fibFormula.html#Binetneg