the pendulum of an old clock is 90 cm long. It swings from side to side through an angle of 10 degrees. How wide must the clock case be made so that the pendulum can swing freely?
Please show working/explanation too please!
+128657 We can use the Law of Cosines to determine the width :
Width^2 = 2*90^2 - 2*90^2*cos(10)
Width = sqrt (2*90^2 - 2*90^2*cos(10)) = sqrt(246.1144012056) = about 15.688 cm [ confirming guest's answer ]
Note to guest.....answers are good, but just providing answers without showing the questioner how you arrived at them is of little value.......!!!!
15.688 cm width if there is no 'Bob' on the end of the pendulum (which would make the end wider)
+128657 We can use the Law of Cosines to determine the width :
Width^2 = 2*90^2 - 2*90^2*cos(10)
Width = sqrt (2*90^2 - 2*90^2*cos(10)) = sqrt(246.1144012056) = about 15.688 cm [ confirming guest's answer ]
Note to guest.....answers are good, but just providing answers without showing the questioner how you arrived at them is of little value.......!!!!
