+131 If a red bag contains ball s numbered 1 to 20, and a blue bag contains ball s numbered 21 to 41.
Can you move a ball from the blue bag to the red bag, and then another ball from the red bag to the blue bag, and again from the blue bag to the red bag, and so on, in such a way as to make the contents of the red bag go through all the possible combinations without repetition?
+118609 Beats me.
There are 20 b***s in the red bag and 21 b***s in the blue bag
There is 41C20 combination are possible
269128937220 = 2.6912893722e11
That is a lot of combinations!
+118609 Hi guest. It is mind blowing!
Here is something else that might b**w you mind.Say your mum gives you 1c allowance for the first week of January.
That is pretty useless you say - might as well throw it away!
BUT
then each week after that she gives you double as much as she geve you last times.
So in week 2 you get 2c
week3 4c
week 4 8c
You have still only got a total of 1+2+4+8 = 15c
week 5 16c
week 6 32c
week 7 64c
week 8 $1.28
week 9 $2.56
by the time you get to the end of the year - week 52 you will get 2^51 approx 2.2518*10^15 cents
That is week 52 $ 22,518,000,000,000
How is that for mind blowing :)
