Complex Numbers

Hi Shades :)

Multiply (6 cis 300o)(2 cis 30o) and express the answer in rectangular form. {nl} {nl} I know how to express this in polar form, but how do I put it into rectangular form?

$(6 e^{300^{0}i})*(2e^{30^0i})\\~\\ =12e^{330^0i}\\~\\ =12(cos330+isin330)\\~\\ =12(cos30-isin30))\\~\\ =12(\frac{\sqrt3}{2}-i*\frac{1}{2})\\~\\ =6\sqrt3-6i$

That's exactly how it is supposed to look at the end. Thank you very much!

You are very welcome Shades :)

You probably already have a good text book but I found this online.  Maybe it will be helpful.

https://www.adelaide.edu.au/mathslearning/bridging/resources/MT5ComplexBook_Feb2013.pdf

Very nice, Melody !!!

A quick question, why are we simplifying the angles to 30^o instead of 60^o? 330^o is 60⁰ more than 270^o so wouldn't the angles be simplified to 60^o?

Thanks Chris . :D

I have answered Shades's  last question  - he must have posted it somewhere else :/