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1. Given that z is a standard Normal random variable, find the following probabilities: (6 Points)

a. P(z <0.52)

b. P(z > -0.63)

c. P(-0.31<z<1.345)

 

Any help with calculations would be greatly appreciated - thanks very much.

 Feb 1, 2016
 #1
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Are you using a table or a calculator?

If you are using a TI-84+ calculator, press (2nd) (DISTR) and 2:normalcdf(

To find P(z<0.52), you can used normalcdf(-100,0.52) to get . 0.698.

To find P(z>-0.63), you can use normalcdf(-0.63,100) to get 0.736.

To find P(-0.31<z<1.345), you can use normalcdf(-0.31,1.345) to get 0.529.

(The answers are rounded.)

You needn't use -100 for the left-hand limit or 100 for the right-hand limit, but you should use numbers <-6 or >+6 for the limits.

 Feb 1, 2016

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