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A hollow cylinder, closed at both ends, has a volume of 250.0mL and contains 4.60g of argon gas. A 90.0g cube of sodium (density = 970.0 g/L) is inserted into the tube in such a way that no gas escapes. What is the density of the gas afterwards??

Please write full equation. (# of...)

Guest Oct 23, 2014

#1
+26402
+5

Note that density = mass/volume.

The volume occupied by the sodium is Vsodium = 90/970 L = 1000*90/970 mL or 92.78mL.

This reduces the volume available for the gas, so its new density = 4.6/(250 - 92.78) g/mL

$${\frac{{\mathtt{4.6}}}{\left({\mathtt{250}}{\mathtt{\,-\,}}{\mathtt{92.78}}\right)}} = {\frac{{\mathtt{230}}}{{\mathtt{7\,861}}}} = {\mathtt{0.029\: \!258\: \!364\: \!075\: \!817\: \!3}}$$

new density ≈ 0.029 g/mL

.

Alan  Oct 23, 2014
Sort:

#1
+26402
+5

Note that density = mass/volume.

The volume occupied by the sodium is Vsodium = 90/970 L = 1000*90/970 mL or 92.78mL.

This reduces the volume available for the gas, so its new density = 4.6/(250 - 92.78) g/mL

$${\frac{{\mathtt{4.6}}}{\left({\mathtt{250}}{\mathtt{\,-\,}}{\mathtt{92.78}}\right)}} = {\frac{{\mathtt{230}}}{{\mathtt{7\,861}}}} = {\mathtt{0.029\: \!258\: \!364\: \!075\: \!817\: \!3}}$$

new density ≈ 0.029 g/mL

.

Alan  Oct 23, 2014

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