+0

# @CPhill

0
1
54
2
+18

Hey, could you help me with this question???

Solve the equation for the solution in the indicated interval.

$$\sqrt[2]{3}sec3\theta-2=0$$    [0°,720°]  $$\leftarrow$$Interval

also, could you explain steps??

dom6547  Nov 30, 2017
edited by dom6547  Nov 30, 2017
Sort:

#1
+79819
+2

√3sec (3θ) -  2  = 0   add 2 to each side

√3sec (3θ)  =   2        divide both sides by  √3

sec (3θ )  =  2  / √3

Let q  =  3θ

sec (q)   = 2  / √3

And this happens when cos (q)  = √3 / 2    .....so....

q  =  30°,  330°, 390°, 690°, 750°, 1050° , 1110°, 1410°, 1470°, 1770°, 1830°, 2130°

So  3θ  =   30°,  330°, 390°, 690°, 750°, 1050°, 1110°, 1410°, 1470°, 1770°, 1830°, 2130°

Divide each side by 3

θ  =  10°, 110°, 130°, 230°, 250°, 350°, 370°, 470°, 490°, 590°, 610°, 710°

Here's the graph :  https://www.desmos.com/calculator/yj6jsij1kc

CPhill  Nov 30, 2017
#2
+18
+2

THANK YOU MUCH!!!

dom6547  Nov 30, 2017

### 2 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details