Derivative of...

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(4sinx)^3cosx-4sinx(cosx)^3

Guest Nov 26, 2014

+118613

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Best Answer

$$\\\frac{d}{dx} (4sinx)^3cosx-4sinx(cosx)^3\\\\
=3(4sinx)^2*4cos^2x\;+\;-sinx(4sinx)^3-[4cosx(cosx)^3+12sinx(cosx)^2*-sinx]\\\\$$

$$\\=12*16sin^2xcos^2x-64sin^4x-[4cos^4x-12sin^2xcos^2x]\\\\$$

And you can simplify it

Melody Nov 26, 2014

Melody · Answer 1 · 2014-11-26T03:07:47

$$\\\frac{d}{dx} (4sinx)^3cosx-4sinx(cosx)^3\\\\
=3(4sinx)^2*4cos^2x\;+\;-sinx(4sinx)^3-[4cosx(cosx)^3+12sinx(cosx)^2*-sinx]\\\\$$

$$\\=12*16sin^2xcos^2x-64sin^4x-[4cos^4x-12sin^2xcos^2x]\\\\$$

And you can simplify it