How do I differentiate these with respect to x: ln(x+2)/(x+2)
and y = (x + 1)(2x – 3)^4.
Thankyou!
+118608 $$\\y=\frac{ln(x+2)}{x+2}$$
use quotient rule
$$\\If \;\;y=\frac{u}{v}\\\\
y'=\frac{vu'-uv'}{v^2}\\\\\\
u=ln(x+2)\\
u'=\frac{1}{x+2}\\\\
v=x+2\\
v'=1\\\\\\$$
Can you finish it?
+118608
$$y = (x + 1)(2x-3)^4$$
for this one you will use the product rule
y=uv
y'=uv'+vu'
u=x+1 u'=1
v=(2x-3)^4 v'=[4(2x-3)^3]*2=8(2x-3)^3
and from here you should be able to finish it 
Thankyou I have the right answer for the first path but I am struggling with the second one. I end up with something really long, I definitely used the right product rule: f(x)g'(x)+g(x)f'(x), which I know is the same as your uv one but I get stuck after I end up with:
(x+1)8(2x-3)^3 + (2x-3)^4
Thankyou!
