I've got a question that goes:
"Person drank 22 litres of alcohol in 1987. In 2001 it's down to 9.3 litres of alcohol per person."
Assignment: Find the %-drop.
The result list says that it's 5.97% - I'm having issues getting to that number.
Mmmmm.....OK.......I didn't see the words " yearly % percent drop" anywhere in the question......!!!
Here's how to solve this :
9.3 = 22 (1 - r)^14 where r is the percent decrease [ in decimal form] per year
Divide both sides by 22
9.3 / 22 = (1 - r)^14
Take the log of both sides :
log (9.3 / 22) = log (1 - r)^14
And by a log property, we can write :
log (9.3 / 22) = 14 * log (1 - r)
Divide both sides by 14
log (9.3 / 22) / 14 = log (1 - r)
And....in exponential form we have
10^ [ log (9.3 / 22) / 14 ] = 1 - r
Rearrange
r = 1 - 10^ [ log (9.3 / 22) / 14 ] = about 0.0596489... or about 5.96489% per year
"Person drank 22 litres of alcohol in 1987. In 2001 it's down to 9.3 litres of alcohol per person."
Assignment: Find the %-drop.
The result list says that it's 5.97% - I'm having issues getting to that number.
1 - (9.3/22)=0.5773 X 100=57.73% decrease in alcohol consumption in 14 years from 1987 to 2001
So that 1 - .5773=.4227^1/14=.94035-1=-.05965 X 100=-5.97%decrease in alcohol consumption per year from 1987 to 2001.
I'll try to be a bit more thorough.
The things I'm told is:
"In 2001 each Greenlandish person drank 9.3 litres of pure alcohol, which is a lot less than what they did in the 1980's. Their alltime highest was in 1987, where they topped at 22 litres of alcohol per citizen per year."
Assignment:
"Read the thing above. Define, with two decimals, the average yearly percentage drop in alcohol consumption per person in the period 1987-2001."
It's Math where I have to explain what I do and such, so I'm given the results-list from the beginning.
The result according to this list is 5.97% (drop on average per year per person).
However, despite many attempts, different approaches I'm no where near this number.
I had one at 6.3%
r=1+−14√9.3/22(add 9.3_14, and 22_0)
And I tried:
r=1−−15√9.3/22(22_15/9.3_0)
Which was 5.9081%
I've tried talking it with a math buddy of mine, none of us managed to get it to the right result of "a drop of 5.97%"
Oh, #3 you wrote that as I did mine.
You're way seems right, I'll take a look at it and try to see if I understand it correctly. Thank you!
Guest #5
It is actually very simple. If you don't understand it, just let me know. Guest #3.
Mmmmm.....OK.......I didn't see the words " yearly % percent drop" anywhere in the question......!!!
Here's how to solve this :
9.3 = 22 (1 - r)^14 where r is the percent decrease [ in decimal form] per year
Divide both sides by 22
9.3 / 22 = (1 - r)^14
Take the log of both sides :
log (9.3 / 22) = log (1 - r)^14
And by a log property, we can write :
log (9.3 / 22) = 14 * log (1 - r)
Divide both sides by 14
log (9.3 / 22) / 14 = log (1 - r)
And....in exponential form we have
10^ [ log (9.3 / 22) / 14 ] = 1 - r
Rearrange
r = 1 - 10^ [ log (9.3 / 22) / 14 ] = about 0.0596489... or about 5.96489% per year