#4**+5 **

Initial momentum of the system = 0.

Crate acceleration along ramp = g*3/5 (component of g along ramp)

Velocity of crate (along ramp) at B given by v^2 = 2*(g*3/5)*L (L = length of ramp).

Horizontal component of crate velocity v_{crate} = -v*4/5 (with horizontal velocity positive to the right).

Momentum of system when crate reaches B: m_{crate}*v_{crate} + m_{ramp}*v_{ramp} = 0

See if you can take it from here.

Alan
Jan 5, 2016

#5**+5 **

Best Answer

This is cool!

OK I get 8.93 feet in one second. What do you get XV

Dragonlance
Jan 5, 2016