(2^3)^2 =

For the first, remember that  ( a^m ) ⁿ  =   a ^{m x n}

So we have

(2 ³ ) ²  = 2 ^{3 x 2} =   2 ⁶  = 64

For the second, remember the rule that  aⁿ x a^m   =  a^m+n

So...... 2³ x 2² = 2³⁺² = 2⁵  = 32

Does that help ??

1st : 2^6

2nd : 2^5

  please explain how  thx :)

the first one : u multiplie 3 by 2

the second one : u add 3 and 2

 thx m8