how do I rearrange the equation
z1 + p1/9.8 + v12/2g = z2 + p2/9.8 + v22/2g + Hf
so that I can find the value of p2 ?
Solve for p2: NOTE: Hf=H
0.102041 p1+(g v12)/2+z1 = H+0.102041 p2+(g v22)/2+z2
0.102041 p1+(g v12)/2+z1 = (5 p1)/49+(g v12)/2+z1 and H+0.102041 p2+(g v22)/2+z2 = H+(5 p2)/49+(g v22)/2+z2:
(5 p1)/49+(g v12)/2+z1 = H+(5 p2)/49+(g v22)/2+z2
(5 p1)/49+(g v12)/2+z1 = H+(5 p2)/49+(g v22)/2+z2 is equivalent to H+(5 p2)/49+(g v22)/2+z2 = (5 p1)/49+(g v12)/2+z1:
H+(5 p2)/49+(g v22)/2+z2 = (5 p1)/49+(g v12)/2+z1
Subtract H+(g v22)/2+z2 from both sides:
(5 p2)/49 = -H+(5 p1)/49+(g v12)/2-(g v22)/2+z1-z2
Multiply both sides by 49/5:
Answer: | p2 = -(49 H)/5+p1+(49 g v12)/10-(49 g v22)/10+(49 z1)/5-(49 z2)/5