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how do I rearrange the equation

z1 + p1/9.8 + v12/2g = z2 + p2/9.8 + v22/2g + Hf

so that I can find the value of p2 ?

 Jun 23, 2016
 #1
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Solve for p2:       NOTE: Hf=H
0.102041 p1+(g v12)/2+z1 = H+0.102041 p2+(g v22)/2+z2

 

0.102041 p1+(g v12)/2+z1 = (5 p1)/49+(g v12)/2+z1 and H+0.102041 p2+(g v22)/2+z2 = H+(5 p2)/49+(g v22)/2+z2:
(5 p1)/49+(g v12)/2+z1 = H+(5 p2)/49+(g v22)/2+z2

 

(5 p1)/49+(g v12)/2+z1 = H+(5 p2)/49+(g v22)/2+z2 is equivalent to H+(5 p2)/49+(g v22)/2+z2 = (5 p1)/49+(g v12)/2+z1:
H+(5 p2)/49+(g v22)/2+z2 = (5 p1)/49+(g v12)/2+z1

 

Subtract H+(g v22)/2+z2 from both sides:
(5 p2)/49 = -H+(5 p1)/49+(g v12)/2-(g v22)/2+z1-z2

 

Multiply both sides by 49/5:
Answer: |  p2 = -(49 H)/5+p1+(49 g v12)/10-(49 g v22)/10+(49 z1)/5-(49 z2)/5

 Jun 23, 2016
 #2
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(z1 + p1/9.8 + v1^2/2g - z2 - v2^2/2g - Hf) / 9.8 = p2

 Jun 23, 2016
 #3
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p2 = 9.81(z1 + p1/9.8 + v12/2g - z2 - v22/2g - Hf)

 

Thanks

 Jun 24, 2016

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