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Factor completely:

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 Jul 26, 2014

Best Answer 

 #1
avatar+4473 
+8

3v^3*y^4 - 48v^3

1. We can factor out 3v^3 from both terms -->

3v^3(y^4 - 16)

2. We can further factor out (y^4 - 16) -->

3v^3(y^2 + 4)(y^2 - 4)

3. Finally, we can factor out (y^2 - 4) -->

3v^3(y^2+4)(y + 2)(y - 2)

 Jul 26, 2014
 #1
avatar+4473 
+8
Best Answer

3v^3*y^4 - 48v^3

1. We can factor out 3v^3 from both terms -->

3v^3(y^4 - 16)

2. We can further factor out (y^4 - 16) -->

3v^3(y^2 + 4)(y^2 - 4)

3. Finally, we can factor out (y^2 - 4) -->

3v^3(y^2+4)(y + 2)(y - 2)

AzizHusain Jul 26, 2014

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