+0  
 
0
442
5
avatar

1: 16n²-8n-5(2n-1)²

2: (x-2)(x+3)-6x

3: y^(6)-1

4: 3p²-7p-6

5: (x+1)²-(y+1)²

Fast thx

 Oct 24, 2014

Best Answer 

 #5
avatar+118608 
+5

I have not done the rest but I will give you hints on where I would start.

 

2) Try expanding and simplifying first and see if that helps

3) Think of it as  ((y^3)^2-1^2) and go from there.

4) standard factorising

5) It is a difference of 2 squares.

 

you have a go and get back with what you have found/done.  We can take it from there.  :)

 Oct 24, 2014
 #1
avatar+118608 
0

Are you asking us to do it fast?

Do you know how rude that sounds?

 Oct 24, 2014
 #2
avatar
0

Sorry... 

 Oct 24, 2014
 #3
avatar
0

Guest Oct 24, 2014
 #4
avatar+118608 
+5

$$\\1)\\\\
8n(2n-1)-5(2n-1)(2n-1)\\
=8n(2n-1)+(-10n+5)(2n-1)\\
=(8n-10n+5)(2n-1)\\
=(-2n+5)(2n-1)\\
=(5-2n)(2n-1)\\$$

 

Have you tried to do these for yourself?

 Oct 24, 2014
 #5
avatar+118608 
+5
Best Answer

I have not done the rest but I will give you hints on where I would start.

 

2) Try expanding and simplifying first and see if that helps

3) Think of it as  ((y^3)^2-1^2) and go from there.

4) standard factorising

5) It is a difference of 2 squares.

 

you have a go and get back with what you have found/done.  We can take it from there.  :)

Melody Oct 24, 2014

6 Online Users

avatar
avatar
avatar